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Home/ Questions/Q 1045409
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T15:58:50+00:00 2026-05-16T15:58:50+00:00

May be this is the basic Question. But i am not able to understand

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May be this is the basic Question. But i am not able to understand how to get it.
My browser url is http://testweb/edit.htm'.
testweb is context path. This uri is from Spring. I need to get edit.htm which is after context, in my jsp. How to get this. Thank you for the support

Thanks,
Santha/

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  1. Editorial Team
    Editorial Team
    2026-05-16T15:58:51+00:00Added an answer on May 16, 2026 at 3:58 pm

    The HttpServletRequest offers several methods to access (parts of) the request URL, among others the HttpServletRequest#getRequestURI() and #getServletPath().

    That said, this job should be done in a Filter or maybe a Servlet rather than a JSP file.


    Update: you seem to be using Spring and rather be interested in the request URI which called the forwarded JSP. You can get it as request attribute with the key RequestDispatcher#FORWARD_REQUEST_URI as follows:

    String uri = request.getAttribute(RequestDispatcher.FORWARD_REQUEST_URI);
    

    or in JSP EL as follows:

    ${requestScope['javax.servlet.forward.request_uri']}
    
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