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Home/ Questions/Q 8512565
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T04:18:48+00:00 2026-06-11T04:18:48+00:00

Maybe i’m just up too late. I have an object that is a thin

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Maybe i’m just up too late.

I have an object that is a thin wrapper around a dictionary. It will pretend to have a property for any key in the dictionary, and return None if a nonexistent key is referenced.

I want to get back only the unique, “truthy” values for three possible keys. (not None). the object may not have one or more of the keys. Or, it may have the same value in two or three of the keys.

This code does what I want:

set(getattr(obj, field) for field in ['field1', 'field2', 'field3'] if getattr(obj, field))

I just don’t like the look of repeating getattr() twice. I feel like i’m overlooking an obviously better way to do this.

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  1. Editorial Team
    Editorial Team
    2026-06-11T04:18:49+00:00Added an answer on June 11, 2026 at 4:18 am

    You could filter out the None values afterwards:

    set(filter(bool, [getattr(obj, field) for field in ['field1', 'field2', 'field3']]))
    

    Or you could just forget about the object. This is probably the way I would do it:

    a_dict = {'key1': 1, 'key2': 2, 'key3missing': 3}
    
    print set([a_dict[key] for key in ['key1','key2','key3'] if key in a_dict])
    
    # prints: set([1, 2])
    
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