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Home/ Questions/Q 7780629
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T18:57:38+00:00 2026-06-01T18:57:38+00:00

Maybe I’m missing something here, but array_diff() seems to be leaving me empty kesys

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Maybe I’m missing something here, but array_diff() seems to be leaving me empty kesys at the end of an array.

With this example data –

$term_ids = array(0 => 242, 1 => 270);
$term_ids = array_diff($term_ids, array(242, 243, 266, 267, 268, 269));

I am being left with this –

Array
(
    [1] => 270
    [0] => 
)

From what I understand, this is incorrect ([0] should be unset, leaving just [1]). I am using $term_ids = array_values($term_ids); after to make the keys correct, but it seems that this should not be necessary, so I’m wondering if someone who knows more than me could clarify?

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  1. Editorial Team
    Editorial Team
    2026-06-01T18:57:40+00:00Added an answer on June 1, 2026 at 6:57 pm

    I tried

    <?php
    
    $arr1 = array(15, 16, 17,18);
    $arr2 = array(15, 17);
    
    $arr3 = array_diff($arr1, $arr2);
    
    var_dump($arr3);
    

    ?>

    and I got [1] => 16, [3] => 18.

    This actually seems to be the intended result as the example on the offical page shows.

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