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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T12:57:04+00:00 2026-05-25T12:57:04+00:00

Maybe this is a simple question but I could not find anything on google

  • 0

Maybe this is a simple question but I could not find anything on google or this site.
So if I have

var myNamespace = {

    foo: function() {
    },

    bar: function() {
    }
};

how would i load both foo() and bar() without having to do it one by one, e.g.

<script type="text/javascript">
    $(document).ready(function(){
        myNamespace.foo();
        myNamespace.bar();
        .
        .
        .
    });
</script>
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  1. Editorial Team
    Editorial Team
    2026-05-25T12:57:04+00:00Added an answer on May 25, 2026 at 12:57 pm

    I’ve not tested this, but something like this should prove useful.
    Every function in JavaScript has a call() method for invoking it. Then:

    
    $(document).ready(function() {
      $.each(myNamespace, function(index, obj) {
        if (typeof(obj) == 'function')
        {
           obj.call(myNamespace);
        }
      });
    });
    
    

    If you need to replace the this scope reference, you could patch this up with jQuery.proxy.

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