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Asked: 2026-06-12T11:45:38+00:00

Me again, In this case I have an accountingcode table [ACCOUNTINGCODE] with the fields:

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Me again,

In this case I have an accountingcode table [ACCOUNTINGCODE] with the fields:
ACC1CUST (example: IVMA)
ACC2DATE (example: 12)
ACC3NROFPROJ (example: 05)
ACC4USER (example: JD)

Let me explain.
These is the example of an accountingcode:
IVMA-12-01-JD
IVMA-12-02-RP
IVMA-12-03-WD
IVMA-12-04-JD

ACC1CUST is filled with a NAMECODE of a [CUSTOMER].
ACC2DATE are the 2 end numbers of the year the [ACCOUNTINGCOE] is made by the user.
ACC3NROFPROJ is the number of projects of the same [CUSTOMER] in the same year. So ACC1CUST, ACC2DATE and ACC3NROFPROJ depend on each other.
ACC4USER is the NAMECODE of the [EXECUTOR] so this is not so important here.

I made a generator query. This generator counts +1 on the MAX projects which he has in the [ACCOUNTINGCODE]. But my code isn’t depending on the the year (ACC2DATE). So if I already have IVMA-12-01-JD and next I place IVMA-13 it won’t start over at 01, but continues at 02. Ofcourse, because my code is checking the amount of projects of the ACC1CUST.

My query is: 

$projectcount="
SELECT accountingcode.custid, customer.custid, MAX(acc3nrofproj) as 'projects'
FROM accountingcode, customer
WHERE accountingcode.custid= customer.custid
AND customer.custid = '$custid'
";

$result3=mysql_query($projectcount) or die("query fout " . mysql_error() );
while( $record3=mysql_fetch_array($result3) )
{
$projectcount=$record3['projects'];
$projectcount = $projectcount+1;
$format = '%1$03s';
$formatprojectcount = sprintf($format, $projectcount);
}

But this doesn’t make any difference if you start a new year which doesn’t exists already in ACC2DATE.

Anyone any idea how I can make this work?

Thank you alot in advance!

FOUND IT

    $projectcount="
      SELECT accountingcode.custid, accountingcode.acc2date, MAX(acc3nrofproj) as 'projects'
      FROM accountingcode, customer
      WHERE accountingcode.custid= customer.custid
      AND customer.custid = '$custid'
      AND acc2date = '$formatdatefrom'
      ";

    $result3=mysql_query($projectcount) or die("query fout " . mysql_error() );
    while( $record3=mysql_fetch_array($result3) )
    {
        $projectcount=$record3['projects'];
        $projectcount = $projectcount+1;
        $format = '%1$03s';
        $formatprojectcount = sprintf($format, $projectcount);
    }
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1 Answer

  1. Editorial Team
    for($i = $startYear/*03, Let's say.*/; i <= $endYear /*12?*/; i++)
{

    $projectcount="SELECT accountingcode.custid, customer.custid, MAX(acc3nrofproj) as 'projects'
      FROM accountingcode, customer
      WHERE accountingcode.custid= customer.custid
      AND customer.custid = '$custid'
      AND ACC2DATE = $i";

    $result3=mysql_query($projectcount) or die("query fout " . mysql_error() );
    while( $record3=mysql_fetch_array($result3) )
    {
        $projectcount=$record3['projects'];
        $projectcount = $projectcount+1;
        $format = '%1$03s';
        $formatprojectcount = sprintf($format, $projectcount);
    }
}

    Use the above query in a for loop starting from a baseYear to the final year.

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