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Home/ Questions/Q 8388351
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T18:27:21+00:00 2026-06-09T18:27:21+00:00

Me and a friend are working on a project, and We have to create

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Me and a friend are working on a project, and We have to create a script that can go into a file, and replace all occurances of a certain expression/word/letter with another using Sed. It is designed to go through multiple tests replacing all these occurances, and we don’t know what they will be so we have to anticipate anything. We are having trouble on a certain test where we need to replace ‘l*’ with ‘L’ in different files using a loop. The code that i have is

#!/bin/sh
p1="$1"

shift

p2="$1"

shift

for file in "$@" #for any file in the directory
do
   # A="$1"

    #echo $A
    #B="$2"
    echo "$p1" | sed -e 's/\([*.[^$]\)/\\\1/g' > temporary #treat all special characters as plain text
    A="`cat 'temporary'`"
    rm temporary
    echo "$p1"
    echo "$file"
    sed "s/$p1/$p2/g" "$file" > myFile.txt.updated #replace occurances 
    mv myFile.txt.updated "$file"
    cat "$file"
done

I have tried testing this on practice files that contain different words and also ‘l*’ But whenever i test it, it deletes all the text in the file. Can someone help me with this, we would like to get it done soon. Thanks

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T18:27:22+00:00Added an answer on June 9, 2026 at 6:27 pm

    It looks like you are trying to set A to a version of p1 with all special characters escaped. But you use p1 later instead of A. Try using the variable A, and also try setting it without a temporary file:

    A=$( echo "$p1" | sed -e 's/\([*.[^$]\)/\\\1/g' )
    
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