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Home/ Questions/Q 6927779
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T11:05:59+00:00 2026-05-27T11:05:59+00:00

MemoryManager openMemory() { if (…) { return memory_manager_instance; } else return NULL; } MemoryManager

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MemoryManager openMemory() {
  if (...) {
    return memory_manager_instance;
  }
  else 
    return NULL;
}

MemoryManager is the name of a user defined C++ class. The function definition above gives me the error in the title.

Basically I don’t want to return an instance when the condition does not hold. Such definition of function is valid and what I usually do in Java, but it seems not working in C++. What should I do to tackle this?

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  1. Editorial Team
    Editorial Team
    2026-05-27T11:05:59+00:00Added an answer on May 27, 2026 at 11:05 am

    Have your function return a MemoryManager * (perhaps using one of the several smart pointer classes available in the C++ library or in boost). If MemoryManager is the name of a class, then this function as written returns a copy of memory_manager_instance. This is different from Java, where a variable of type MemoryManager would be a reference to an object.

    EDIT: Further, it looks like you are trying to implement a singleton. You’d want to make the default constructor, copy constructor, and assignment operator for MemoryManager private or protected. The first two are in Java as well, but not the last!

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