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Home/ Questions/Q 8989025
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T22:09:06+00:00 2026-06-15T22:09:06+00:00

Microsoft SQL Server 2008 A worker lives in some Country, and may have more

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Microsoft SQL Server 2008

A worker lives in some Country, and may have more than one job, with more than one salary.

I want to get the average for each country’s individual total salary.

Tables:

1) countries(country_id, name)

2) people(ssn, name,country_id)

3) jobs(ssn, job_title, salary)

[countries]

  • 1, usa
  • 2, germany

[people]

  • 010101, John, 1
  • 020202, Lee, 1
  • 030303, Harry, 2

[jobs]

  • 010101, teacher, 3200
  • 010101, builder, 1500
  • 020202, actor, 45000
  • 020202, singer, 200000
  • 030303, producer, 120000

Needed Query Result:

each country’s average (for each country) = sum of each worker’s total salaries) / number of workers

Country – Average Salary

  • usa – 124850
  • germany – 120000
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T22:09:07+00:00Added an answer on June 15, 2026 at 10:09 pm

    This should work for you:

    select Salary / count(c.name) AvgSalary, c.Name
    from people p
    inner join 
    (
      select sum(salary) Salary, p.country_id
      from jobs j
      left join people p
        on j.ssn = p.ssn
      group by p.country_id
    ) sal
      on p.country_id = sal.country_id
    left join countries c
      on p.country_id = c.country_id
    group by salary, c.Name;
    

    See SQL Fiddle with Demo

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