Question

min(gameinfo.not_my_planets.values(), key=lambda p: p if p.num_ships < 35)

Trying to get the minimum planet but only while there are planets that have 35 or less ships.

get unexpected token ‘)’ though any ideas?

Answer 1

You missed else part in lambda expression, but you better Rewrite it to:

min(filter(lambda p: p.num_ships < 35, gameinfo.not_my_planets.values()))

filer(...) will reduce the sequence of planets to those having num_ships < 35. Are planet objects comparable among them selves or should you compare to an attribute planet,
planet.size? If so, you have to add another lambda:

min(filter(lambda p: p.num_ships < 35, gameinfo.not_my_planets.values()), key=lambda p:p.size)

If you are not used to functional constructs, just use simple list comprehension (I assumed planets are comparable among them selves):

min( p for p in gameinfo.not_my_planets.values() if p.num_ships < 35)