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Home/ Questions/Q 7666845
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T14:56:25+00:00 2026-05-31T14:56:25+00:00

Model One class One < ActiveRecord::Base before_save :do_stuff private def do_stuff two = Two.find(8)

  • 0

Model “One”

class One < ActiveRecord::Base
  before_save :do_stuff

  private
    def do_stuff
      two = Two.find(8)
      two.field2 = 'Value'
      two.save!
    end
end

Model “Two”

class Two < ActiveRecord::Base
  before_save :do_stuff

  private
    def do_stuff
      one = One.find(7)
      one.field2 = 'SomeValue'
      one.save!
    end
end

Executing:

two = Two.find(1)
two.somefield = 'NewVal'
two.save!

Infinite loop will start. What would be most ruby-on-rails way to implement two models that must change each other on before_save callback?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T14:56:26+00:00Added an answer on May 31, 2026 at 2:56 pm

    On the hopefully rare occasions you need to do this, you might want to disable your before_save filter using an attr_accessor or move it to an after_save block to avoid looping.

    For example:

    class One < ActiveRecord::Base
      attr_accessor :not_doing_stuff
      before_save :do_stuff,
        :unless => :not_doing_stuff
    
    private
      def do_stuff
        two = Two.find(8)
        two.field2 = 'Value'
        two.save!
      end
    end
    

    You’d disable the trigger on at least one of them:

    class Two < ActiveRecord::Base
      before_save :do_stuff
    
    private
      def do_stuff
        one = One.find(7)
        one.not_doing_stuff = true
        one.field2 = 'SomeValue'
        one.save!
      end
    end
    

    Things like this are always very ugly, so try and avoid it unless you can think of no other way. If you need it, make sure you’ve written enough unit tests to ensure it won’t lock into an endless loop under some edge cases.

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