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Home/ Questions/Q 995811
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T06:46:49+00:00 2026-05-16T06:46:49+00:00

Modern C++ Design gives the following example: template <class T> struct EnsureNotNull { static

  • 0

Modern C++ Design gives the following example:

template <class T> struct EnsureNotNull
{
    static void Check(T*& ptr)
    {
      if (!ptr) ptr = GetDefaultValue();
    }
};

template
<
   class T,
   template <class> class CheckingPolicy = EnsureNotNull,
   template <class> class ThreadingModel
>
class SmartPtr
  : public CheckingPolicy<T>
  , public ThreadingModel<SmartPtr>
{
...
  T* operator->()
  {
    typename ThreadingModel<SmartPtr>::Lock guard(*this);
    CheckingPolicy<T>::Check(pointee_);
    return pointee_;
  }
private:
  T* pointee_;
};

I couldn’t figure how ThreadingModel template would be constructed in a fashion that It could accept SmartPtr as parameter, in my mind some crazy recursion is going to happen. How can this be possible?

Edit:

I’ve tried Potatoswatter (sorry lol) comment:

template <class SmartPtr> struct SingleThreadingModel
{
  class Lock
  {
    public: 
      Lock(SmartPtr&)
      {
      }
  };
};

but it did’nt worked.

here is the error that gcc is giving me:

main.cpp:28:35: error: type/value mismatch at argument 1 in template parameter list for ‘template<class> class ThreadingModel’
main.cpp:28:35: error:   expected a type, got ‘SmartPtr’
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T06:46:50+00:00Added an answer on May 16, 2026 at 6:46 am

    You are trying to pass SmartPtr as a template type argument to ThreadingModel. SmartPtr however is a template, not a concrete type, and the injected class-name is not available in the inheritance list.

    Also note that you can’t just use default arguments for template parameters in arbitrary positions (§14.1/11):

    If a template-parameter has a default template-argument, all subsequent template-parameters shall have a default template-argument supplied.

    Your code with those issues fixed:

    template
    <
      class T,
      template <class> class ThreadingModel,
      template <class> class CheckingPolicy = EnsureNotNull
    >
    class SmartPtr
      : public CheckingPolicy<T>
      , public ThreadingModel<SmartPtr<T, ThreadingModel, CheckingPolicy> > 
    //                         ^ .... now passing a concrete class .... ^
    {
        T* operator->() {
            // the following use of SmartPtr is fine as it is the injected class-name:
            typename ThreadingModel<SmartPtr>::Lock guard(*this);
            // ...
        }
    };
    

    Note that while Modern C++ Design is an excellent book, it can’t replace a good basic book on templates like Vandevoorde/Josuttis.

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