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Home/ Questions/Q 7492401
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T16:25:52+00:00 2026-05-29T16:25:52+00:00

MonoDevelop (2.10.8) is reporting: JPGCorruptForm.cs(20,20): Warning CS0219: The variable `myStream’ is assigned but its

  • 0

MonoDevelop (2.10.8) is reporting:

JPGCorruptForm.cs(20,20): Warning CS0219: The variable `myStream' is assigned but its value is never used (CS0219) (JPGCorrupt)

For this function:

    private void toolStripButtonChooseText_Click(object sender, EventArgs e)
    {
        Stream myStream = null;
        OpenFileDialog openFileDialog = new OpenFileDialog();

        openFileDialog.InitialDirectory = ".";
        openFileDialog.Filter = "txt files (*.txt)|*.txt|All files (*.*)|*.*";
        openFileDialog.FilterIndex = 1;
        openFileDialog.RestoreDirectory = false;

        if (openFileDialog.ShowDialog() == DialogResult.OK)
        {
            Stop();

            try
            {
                if ((myStream = openFileDialog.OpenFile()) != null)
                {
                    _settings.TextFile = openFileDialog.FileName;
                    CurrentTextFile = _settings.TextFile;
                }

            }
            catch (Exception ex)
            {
                MessageBox.Show("Error: Could not read file from disk. Original error: " + ex.Message);
            }
        }
    }

This is my frist mono test project and I’m not sure if this kind of thing is normal. It certainly is not fatal, but could get annoying.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-29T16:25:53+00:00Added an answer on May 29, 2026 at 4:25 pm

    Well you’re assigning a value to the variable, but you’re never actually reading from it. In other words, you could easily remove it, just changing the middle expression to:

    if (openFileDialog.OpenFile() != null)
    

    Note that your existing code doesn’t actually read from the variable even though you might think it does in the comparison to null. It’s more like this:

    Stream tmp = openFileDialog.OpenFile();
    myStream = tmp;
    if (tmp != null)
    

    It sounds like you probably should be using it, to close the stream if nothing else… although I’d then declare it as late as possible, like this:

    using (Stream myStream = openFileDialog.OpenFile())
    {
        if (myStream != null)
        {
            _settings.TextFile = openFileDialog.FileName;
            CurrentTextFile = _settings.TextFile;
        }
    }
    

    Here’s a simpler example of the same problem, but the way:

    using System;
    
    class Test
    {
        static void Main()
        {
            string x;
    
            if ((x = "Hello") != null)
            {
                Console.WriteLine("Yes");
            }
        }
    }
    

    Note that with warning level 4 (and possibly lower ones), the Microsoft C# 4 compiler picks up on it too:

    Test.cs(7,16): warning CS0219: The variable 'x' is assigned but its value is
            never used
    
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