Question

More specifically, is there a set of values ( a, b and c) for which the operator precedence matters in the statement:

var value = (a && b == c); 

(with the exception of NaN).

Answer 1

Yes

js> false && true == false false js> (false && true) == false true 

Since == has higher precedence than &&, the first is parsed as false && (true == false), which is equivalent to false && false, and thus evaluates to false. The second is equivalent to false == false, which is true