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Home/ Questions/Q 679157
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T01:13:44+00:00 2026-05-14T01:13:44+00:00

Most of the time, I am doing this way. class a { public: ~

  • 0

Most of the time, I am doing this way.

class a {
public:
    ~ a() {
        i = 100;          // OK
        delete (int *)j;  // Compiler happy. But, is it safe?
                          // The following code will lead compilation error : delete j;
    }

private:
    volatile int i;
    volatile int *j;
};

int main() {
    a aa;

}

However, I saw an article here:

https://www.securecoding.cert.org/confluence/display/seccode/EXP32-C.+Do+not+access+a+volatile+object+through+a+non-volatile+reference

Casting away volatile allows access to
an object through a non-volatile
reference. This can result in
undefined and perhaps unintended
program behavior.

So, what will be the workaround for my above code example?

Here is the error message I get if I use

delete j

Note that, this is output from VC6 (Don’t ask why I am using VC6!)

c:\projects\a\a.cpp(5) : error C2664:
‘delete’ : cannot convert parameter 1
from ‘volatile int *’ to ‘void *’
Conversion loses qualifiers

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  1. Editorial Team
    Editorial Team
    2026-05-14T01:13:44+00:00Added an answer on May 14, 2026 at 1:13 am

    Nothing. If you don’t access the volatile memory, the semantics of volatile are unaffected. If you accessed volatile memory through a casted non-volatile pointer, the compiler might optimize the reference away. If the value had changed, you’d have the wrong value. For some value of wrong. 😉

    The delete doesn’t access the volatile memory, it just frees it. Sort of an uncommon thing to do with volatile memory.

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