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Home/ Questions/Q 849137
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T07:03:28+00:00 2026-05-15T07:03:28+00:00

Mr. Ayende wrote in his latest blog post about an implementation of a queue

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Mr. Ayende wrote in his latest blog post about an implementation of a queue. In the post he’s using two magical files: BinaryWriterWith7BitEncoding & BinaryReaderWith7BitEncoding

BinaryWriterWith7BitEncoding can write both int and long? using the following method signatures: void WriteBitEncodedNullableInt64(long? value) & void Write7BitEncodedInt(int value)

and

BinaryReaderWith7BitEncoding can read the values written using the following method signatures: long? ReadBitEncodedNullableInt64() and int Read7BitEncodedInt()

So far I’ve only managed to find a way to read the 7BitEncodedInt:

protected int Read7BitEncodedInt()
{
    int value = 0;
    int byteval;
    int shift = 0;
    while(((byteval = ReadByte()) & 0x80) != 0)
    {
        value |= ((byteval & 0x7F) << shift);
        shift += 7;
    }
    return (value | (byteval << shift));
}

I’m not too good with byte shifting – does anybody know how to read and write the 7BitEncoded long? and write the int ?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T07:03:29+00:00Added an answer on May 15, 2026 at 7:03 am

    Here’s something like the write:

        static void Write7BitEncodedInt32(Stream dest, int value)
        {
            Write7BitEncodedUInt32(dest, (uint) value);
        }
        static void Write7BitEncodedUInt32(Stream dest, uint value)
        {
            if(value < 128) { dest.WriteByte((byte)value); return;}
            while(value != 0)
            {
                byte b = (byte) (value & 0x7F);
                value >>= 7; // since uint, we'll eventually run out of 1s
                if (value != 0) b |= 0x80; // and there's more
                dest.WriteByte(b);
            }
        }
    
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