Question

muutujad = list(input("Muutujad (sisesta formaadis A,B,C,...): "))
while "," in muutujad == True:
    muutujad.remove(",")
print (muutujad)

My brain says that this code should remove all the commas from the list and in the end
the list should contain only [“A”,”B”,”C” ….] but it still contains all the elements. When i tried to visualize the code online, it said like [ “,” in muutujad ] is always False but when i check the same command from the console it says it is True. I know it is a simple question but i would like to understand the basics.

Answer 1

You can use a list comprehension instead of a while loop:

muutujad = [elem for elem in muutujad if elem != ',']

Your if test itself is also wrong. You never need to test for == True for if in any case, that’s what if does. But in your case you test the following:

("," in muutujad) and (muutujad == True)

which is always going to be False. In python, comparison operators like in and == are chained. Leaving off the == True would make your while loop work much better.

I’m not sure you understand what happens when you call list() on a string though; it’ll split it into individual characters:

>>> list('Some,string')
['S', 'o', 'm', 'e', ',', 's', 't', 'r', 'i', 'n', 'g']

If you wanted to split the input into elements separated by a comma, use the .split() method instead, and you won’t have to remove the commas at all:

>>> 'Some,string'.split(',')
['Some', 'string']