Question

MVC3 VB.NET Application. I have multiple file upload boxes on a form in my mvc3 application. Request.Files shows 3 files when I put a break point in the below function and look at it.. Problem is other than coding a counter and using a select case I dont see a way to handle saving each file name to the database column it belongs to… Is there away to assign the variable on the fly I guess you could say So that the foreach loop would drop the file in the correct column.. Ie handoutFile1, handoutFile2 , handoutFile3, Etc…. As it stands the below will overwrite the filename in handoutfile1 every time the loop is gone through….I thought about throwing a counter in the loop and just put a select case on it to assign the db column based on the counter number. Seems like a cheap work around though.

 For Each File As String In Request.Files

                Dim hpf As HttpPostedFileBase = TryCast(Request.Files(File), HttpPostedFileBase)
                If hpf.ContentLength = 0 Then
                    Continue For
                End If

                Dim savedfileName As String = Path.Combine(AppDomain.CurrentDomain.BaseDirectory) + "\CourseHandouts\" + hpf.FileName
                hpf.SaveAs(savedfileName)
                _filename = hpf.FileName
                courses.handoutFile1 = _filename

            Next

Answer 1

I dont know VB.Net but i will try to answer in C# code,

In your action you can define in parameter as

    [HttpPost]
    public ActionResult Index(IList<HttpPostedFileBase> postedFiles)
    {
        foreach (var file in postedFiles)
        {
            //
        }
        return View();
    }

and in the view like the following,

@using (Html.BeginForm("Index", "Home", FormMethod.Post, new { enctype = "multipart/form-data"  }))
{
@Html.ValidationSummary(true)
<fieldset>
    <legend>TestModel</legend>
    @Html.TextBox("postedFiles[0]",null, new { type = "file" })
    @Html.TextBox("postedFiles[1]",null, new { type = "file" })
    @Html.TextBox("postedFiles[2]",null, new { type = "file" })
    <p>
        <input type="submit" value="Create" />
    </p>
</fieldset>
}