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Home/ Questions/Q 541023
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T10:18:03+00:00 2026-05-13T10:18:03+00:00

My apologies if this is too simple a question, I was unable to google

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My apologies if this is too simple a question, I was unable to google it as it did not like searching for %20.

If I have a URL on which I use the getFile() method to obtain the path for a file I would like to open for processing. If the particular file resides in a directory that contains spaces, the path returned would contains %20 where the space should be.

Will a FileReader then be able to use the path as provided, or will I need to replace the %20 with a space?

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  1. Editorial Team
    Editorial Team
    2026-05-13T10:18:03+00:00Added an answer on May 13, 2026 at 10:18 am

    You will need to use URLDecoder yourself. FileReader just uses the String it’s handed, and rightly so – %20 is a perfectly valid character sequence in a file name, and if it were automatically converted you could not access files containing it.

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