Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8121175
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 6, 20262026-06-06T05:24:01+00:00 2026-06-06T05:24:01+00:00

My app has a function where it takes user input and then calls HttpGet

  • 0

My app has a function where it takes user input and then calls HttpGet for the website (in this case, wiktionary). I then cut out the irrelevant parts and parse the rest with jsoup. One particular page is constantly returning an old version of the page source instead of the version that I updated a couple days ago. Is there any way to force it to fetch the new version instead? The app has no cache and unfortunately I have to use HttpGet instead of fetching with jsoup directly because of extraneous information that is too hard to separate without doing it the way I am. I have no way to edit the header of the webpage in question.

This is the relevant code:

DefaultHttpClient httpClient = new DefaultHttpClient();
HttpGet httpGet = new HttpGet(url);
ResponseHandler<String> resHandler = new BasicResponseHandler();
String page="";
Document doc = null;

try {
    page = httpClient.execute(httpGet, resHandler);
    doc = Jsoup.parse(page);
    } catch (IOException e) {
     e.printStackTrace();
}
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-06T05:24:02+00:00Added an answer on June 6, 2026 at 5:24 am

    Try to add a dynamic parameter to the url you want to fetch, like this:

    http://myfancydomain.com/site.html?fetch=123456

    The “123456” should be generated by a random number generator, alternatively you may want to use the current timestamp. The server recognizes this as a “new” request and will deliver the recent version of the site.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

My app has a registered shutdown function and it seems there's some issues with
My app has several buttons which trigger different events. The user should NOT be
My app has a session timeout after 30 minutes. If the user has a
My app has 6 menu items, so the OS shows the first 4, then
I'm writing a very simple CRUD app that takes user stories and stores them
I'm working on a web-app, in which each user has multiple non-local XML files
Background I am writing an Android app whose main function is tracking the user's
I have a CI app that has a auth controller and switchuser function. Basically
I have an android app where user presses a start button and some function
My app has three text fields: 1) Username // Initialization code usernameTextField = [[UITextField

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.