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Home/ Questions/Q 7923591
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T17:22:29+00:00 2026-06-03T17:22:29+00:00

My app has an RSS tableView and at another page a WebView. I can

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My app has an RSS tableView and at another page a WebView. I can open WebView with the click of any item in the RSS but I can’t pass the link and display the website in the WebView
below is my code

(void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath {

    int storyIndex = [indexPath indexAtPosition: [indexPath length] - 1];

    NSString * storyLink = [[stories objectAtIndex: storyIndex] objectForKey: @"link"];


    // clean up the link - get rid of spaces, returns, and tabs...
    storyLink = [storyLink stringByReplacingOccurrencesOfString:@" " withString:@""];
    storyLink = [storyLink stringByReplacingOccurrencesOfString:@"\n" withString:@""];
    storyLink = [storyLink stringByReplacingOccurrencesOfString:@"  " withString:@""];


    [tableView deselectRowAtIndexPath:indexPath animated:NO];

    browserScreen = [[DetailsViewController alloc] initWithNibName:@"DetailsViewController" bundle:nil];
    [self.view addSubview:browserScreen.view];


    // open in Safari --> this line works perfect but I want to open the link in my own Webview so I commented it out
    //[[UIApplication sharedApplication] openURL:[NSURL URLWithString:storyLink]];

 }

thanks for any help!

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  1. Editorial Team
    Editorial Team
    2026-06-03T17:22:34+00:00Added an answer on June 3, 2026 at 5:22 pm

    Assuming the UIWebView is in your DetailsViewController, you have to set the URL in the WebView that is in your DetailsViewController.

    browserScreen.webView.request = [NSURLRequest requestWithURL:[NSURL URLWithString:storyLink]];
    
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