Question

My app has has an option to show screen-B instead of screen-A (default main) at app start up.
First I tried pushScreen(screen-B) in screen-A’s constructor which resulted in display stack has screen-A on top and then screen-B..

What I want to do is:
At start up if the option is on, show screen-B (stack has screen-B then screen-A so that Escape key would lead to screen-A)

What would be the right way to acheive this?

Answer 1

You might consider pushing B a little bit later in the process, in the onUiEngineAttached method:

class ScreenA extends Screen {
    ...
    protected void onUiEngineAttached(boolean attached) {
        if (attached) {
            // check condition and push B as appropriate
        }
    }
}