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Home/ Questions/Q 1114683
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T03:02:32+00:00 2026-05-17T03:02:32+00:00

My app has the following models: user and watch_list. User has attributes id, name

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My app has the following models: user and watch_list. User has attributes id, name and WatchList has attributes user_id, friend_id.

class WatchList < ActiveRecord::Base
  belongs_to :user
  has_many :friends, :class_name => "User", :foreign_key => "friend_id"
end

class User < ActiveRecord::Base
  has_one :watch_list
  has_many :friends, :through => :watch_list

  def friends_with(friend_id)
    self.friends.each do |f|
      if f.id == friend_id
        return true
      end
    end
    return false
  end
end

For some reason when I use @current_user.friends_with(friend_id) I always get ‘true’ as a response. Any ideas why this won’t work right? (I know @current_user works)

Thanks!

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  1. Editorial Team
    Editorial Team
    2026-05-17T03:02:32+00:00Added an answer on May 17, 2026 at 3:02 am

    What are you trying to do with this method? Determining if a user is a friend with another (through watchlist)?
    By convention, in ruby, a method returning either true or false is ended by an interrogation mark…

    You may use the include? Array method directly and do

    @current_user.friends.include?(friend)
    

    In this case, you use the friend object directly and not its id…

    Or write a methode like the following:

    I would try something like:

    def has_a_friend_with_id?(friend_id)
      friends.map(&:id)include? friend_id
    end
    

    I renamed your method in order to have something more meaningful…

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