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Home/ Questions/Q 6706047
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T07:28:27+00:00 2026-05-26T07:28:27+00:00

My application has a picture box in it. When I open an image in

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My application has a picture box in it. When I open an image in Windows, instead of the default program that opens to show that image, I want to use my own application and have that program containing the picture box show the image.

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  1. Editorial Team
    Editorial Team
    2026-05-26T07:28:28+00:00Added an answer on May 26, 2026 at 7:28 am

    I did this recently, though I used a different action, not the default Open action.

    First you find out file type of some extension, say .jpg:

    var imgKey = Registry.ClassesRoot.OpenSubKey(".jpg")
    var imgType = key.GetValue("");
    

    Then you find out the path to your executable and build the “command string”:

    String myExecutable = Assembly.GetEntryAssembly().Location;
    String command = "\"" + myExecutable + "\"" + " \"%1\"";
    

    And register your executable to open files of that type:

    String keyName = imgType + @"\shell\Open\command";
    using (var key = Registry.ClassesRoot.CreateSubKey(keyName)) {
        key.SetValue("", command);
    }
    
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