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Home/ Questions/Q 6944475
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T13:18:42+00:00 2026-05-27T13:18:42+00:00

My application is a specialized file comparison utility and obviously it does not make

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My application is a specialized file comparison utility and obviously it does not make sense to compare only one file, so nargs='+' is not quite appropriate.

nargs=N only excepts a maximum of N arguments, but I need to accept an infinite number of arguments as long as there are at least two of them.

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  1. Editorial Team
    Editorial Team
    2026-05-27T13:18:43+00:00Added an answer on May 27, 2026 at 1:18 pm

    Short answer is you can’t do that because nargs doesn’t support something like ‘2+’.

    Long answer is you can workaround that using something like this:

    parser = argparse.ArgumentParser(usage='%(prog)s [-h] file file [file ...]')
    parser.add_argument('file1', nargs=1, metavar='file')
    parser.add_argument('file2', nargs='+', metavar='file', help=argparse.SUPPRESS)
    namespace = parser.parse_args()
    namespace.file = namespace.file1 + namespace.file2
    

    The tricks that you need are:

    • Use usage to provide you own usage string to the parser
    • Use metavar to display an argument with a different name in the help string
    • Use SUPPRESS to avoid displaying help for one of the variables
    • Merge two different variables just adding a new attribute to the Namespace object that the parser returns

    The example above produces the following help string:

    usage: test.py [-h] file file [file ...]
    
    positional arguments:
      file
    
    optional arguments:
      -h, --help  show this help message and exit
    

    and will still fail when less than two arguments are passed:

    $ python test.py arg
    usage: test.py [-h] file file [file ...]
    test.py: error: too few arguments
    
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