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Home/ Questions/Q 6372045
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T01:10:48+00:00 2026-05-25T01:10:48+00:00

My application merges two std::map instances. If there are no duplicates, the merge completes

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My application merges two std::map instances. If there are no duplicates, the merge completes without intervention. However, if a duplicate is detected, then the method asks whether the new value should be ignored or overwritten. (This query may be answered by a rule table, message box to the user, or some other logic … it is just an instance of a class derived from a pure virtual class with a bool confirm() const method.)

If the insert fails, and they decide to overwrite the existing entry, I already have an iterator pointing to the correct item to update. Can I use this iterator to update the value directly, or do I have to call operator[] and take the hit of another lookup?

// typedef std::map<Foo, Foo, Compare> Dictionary;
// Dictionary this_dictionary, other_dictionary;
for (Dictionary::const_iterator i = other_dictionary.begin();
     i != other_dictionary.end();
     ++i) {
  std::pair<Dictionary::iterator,bool> ret = this_dictionary.insert(*i);
  if (!ret.second && confirmer.confirm()) {
    // ???
  }
}
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  1. Editorial Team
    Editorial Team
    2026-05-25T01:10:49+00:00Added an answer on May 25, 2026 at 1:10 am

    You need to use Dictionary::iterator instead of Dictionary::const_iterator in the return from insert.

    for (Dictionary::const_iterator i = other_dictionary.begin();
         i != other_dictionary.end();
         ++i) {
      // Use standard iterator here
      std::pair<Dictionary::iterator,bool> ret = this_dictionary.insert(*i);
      if (!ret.second && confirmer.confirm()) {
        ret.first->second = i->first; 
      }
    }
    
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