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Home/ Questions/Q 3433546
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T07:35:22+00:00 2026-05-18T07:35:22+00:00

My C++ is pretty rusty so now that I started using it for a

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My C++ is pretty rusty so now that I started using it for a hobby project I got to “level up”-again..

#include "stdafx.h"
#include "stdlib.h"

class a
{
public:
    void call() { printf("CALL called\n"); }
};

class b
{
public:
    b() { this->pointer = new a; }
    void call() { this->pointer->call(); }
private:
    a* pointer;
};

int _tmain(int argc, _TCHAR* argv[])
{
    b t;
    t.call();

    system("PAUSE");
    return 0;
}

Will that result in a memory leak? And how can I delete the pointers if the program decides it does not need them anymore?

Would “delete t” be enough or would that produces a memory leak too?

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  1. Editorial Team
    Editorial Team
    2026-05-18T07:35:22+00:00Added an answer on May 18, 2026 at 7:35 am

    pointer in b is allocated but never deleted. You’ll want to define a destructor for b that deletes a, otherwise you will leak the a pointed to by pointer every time a b goes out of scope:

    b::~b()
    {
        delete pointer;
    }
    
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