Question

My char array would be looking something like below,

Org_arr[1first line text------2second line text----3third line-------4--------------------5fith line text------];

where ‘-‘ equal to blank spaces

The above array contains the control code(0, 1, 2, 3..) after every 20 characters starting from 0-th place.

I would like to convert the above text array into below format,

The blank spaces will be removed and a line feed will be added at the end of each line.

Conv_arr[1first line text/n2second line text/n3third line/n4/n5fith line text/n];

Please suggest a good method to implement this,

Answer 1

the easiest way will be using regular expression to replace pattern “\s?” with “\n”

If you don’t have access to a regex library, you can do something like this

int print_line_break = 1;
char* Conv_arr = (char*)malloc(sizeof(char) * strlen(Org_arr) + 1);

for(char* c=Org_arr; *c; ++c) {
   if (*c == ' ') {
      *(Conv_arr++) = *c;
      print_line_break = 1;
   } else {
      // only print 1 '\n' for a sequence of space
      if (print_line_break) {
         *(Conv_arr++) = '\n';
         print_line_break = 0; 
      }
   }
}

free(Conv_arr);