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Editorial Team
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Asked: 2026-06-15T23:31:49+00:00

my code have an error in update part, it shows for me this error:

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my code have an error in update part, it shows for me this error:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ‘( reqdate= ‘2012-12-17’,lat1= ‘26.18355762868919’,long1= ‘50.30387832641602’,lat’ at line 1

and this is my code about update:

if(mysql_fetch_array($query1))
{
$datex = strtotime(date('Y-m-d H:i:s'))+36000;
$time = date('H:i:s', $datex);
$date=date('Y-m-d', $datex);
$result=mysql_query("SELECT * FROM sensorusers  WHERE uid='$uid'");

mysql_query("UPDATE requests SET ( reqdate= '$date',lat1= '$lat1',long1= '$lng1',lat2= '$lat2',long2='$lng2',lat3='$lat3',long3='$lng3',lat4='$lat4',long4='$lng4',inout='$type',time='$time') WHERE  sid= '$drivers'") or die(mysql_error());

$Alpha  = @mysql_query($query2,$db); //Execute Query

}
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1 Answer

  1. Editorial Team

    just remove the parenthesis and surely it will execute, eg

    UPDATE requests 
SET   reqdate = '$date',
      lat1    = '$lat1',
      long1   = '$lng1',
      lat2    ='$lat2', 
      long2   = '$lng2', 
      lat3    = '$lat3',
      long3   = '$lng3',
      lat4    = '$lat4',
      long4   = '$lng4',
      `inout` = '$type',    // << RESERVED KEYWORD
      time    = '$time' 
WHERE  sid    = '$drivers'

    INOUT is a RESERVED KEYWORD. You should escape it using backtick.

    be warned that this code is vulnerable with SQL Injection, please read the article below to learn how to prevent from it,

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