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Editorial Team
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Asked: 2026-05-27T18:41:16+00:00

My code: <html> <head> <script type=text/javascript charset=utf-8> function backgroundImage() { document.body.style.backgroundImage=’url(http://www.image.jpg)’; } </script> </head>

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My code:

<html>
<head>
<script type="text/javascript" charset="utf-8">
function backgroundImage() {
document.body.style.backgroundImage='url("http://www.image.jpg")';
}
</script>
</head>
<body onLoad="backgroundImage()">
Content here
</body> 
</html>

But the addition of document.ready:

$(document).ready(function () {
document.body.style.backgroundImage='url("http://www.image.jpg")';
});

breaks the code

Why does this not work, something I’m missing, or prefix of document.ready just not needed? Could it be that ‘document’ should not be called twice?

Thanks in advance!

Kind Regards,
Dale

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1 Answer

  1. Editorial Team

    This is no problem, can run

    http://jsfiddle.net/HRhQW/

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