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Home/ Questions/Q 494013
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T05:27:30+00:00 2026-05-13T05:27:30+00:00

My code {% if GET[‘search’] % } {% block count codes|length as counter %}

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My code

{% if GET['search'] % }
            {% block count codes|length as counter %}

Is the following a valid if -clause as a Django tag?

{% if GET['search'] % }

The following code gives me an error that block takes only one argument.
What is wrong in the code?

{% block count codes|length as counter %}
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  1. Editorial Team
    Editorial Team
    2026-05-13T05:27:30+00:00Added an answer on May 13, 2026 at 5:27 am

    Django isn’t PHP.

    You’re trying to use a template filter inside a template tag. You can use either a tag or a filter, but not both.

    For that matter, since the block tag takes only a label for the block, I’m not sure what the template code you’ve written is supposed to do. Additionally, are you sure that GET['search'] is valid syntax in a template tag?

    I’m guessing a little at your view and template requirements, but here’s how I would approach this in your place. There are a number of gaps you’ll have to fill in for yourself depending on your circumstances.

    In views.py:

    from django.shortcuts import render_to_response
    
    def my_view(request):
        request_was_search = False
        codes = []
    
        if request.GET.has_key('search'):
            request_was_search = True
            codes = some_function_you_define_to_get_codes()
    
        return render_to_response('foo.html',
                                  {'codes':codes,
                                   'request_was_search':request_was_search})
    

    In the template:

    {% block count %}
        {% if request_was_search %}
            // do whatever you want here
            <p>There were {{ codes|length }} codes submitted.</p>
            // end example
        {% endif %}
    {% endblock %}
    
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