Question

my code is:-

class Test
{
  static int a = 11;
  static
  {
    System.out.println("Hello static! " + main() + a);
  }

  public static void main(String[]args)
  {
    System.out.println("Hello String!");
  }

  public static char main()
  {
    System.out.println("Hello char!");
    return 'H';
  }
}

Output:-

Hello char!
Hello static! H11
Hello String!

Why “Hello char!” is printed before “hello static!”?

Answer 1

Why “Hello char!” is printed before “hello static!”?

Because, main() method is invoked and executed before the completion of the sysout statement printing Hello static.

Here’s the execution order: –

• Class is loaded.
• static variable a is loaded and initialized to 11.
• static block is executed.
• From sysout statement there, main() static method is invoked. At this point of time Hello static has not been printed yet, because the sysout statement is not complete.
• Execution control goes to main() method. Because without that the current sysout statement cannot complete.
• main() method prints "Hello char", and returns 'H'.
• Execution goes back to static block, inside sysout.
• sysout completes execution, and prints "Hello static! H11"

Note: – sysout above means – System.out.println().