Question

My code is complete minus one little flaw. It searches the array and prints out which values are unique, however it always counts the first entry as unique even if it is followed by the same value. Can anyone look at my code and tell me which part is messing this up because it is driving me crazy.

    #include <stdio.h>
    #define size 7
    int main(void)
    {
        int array1[size], target, answer, found, x, k, prev, count =1, i;

        printf("Please input %d integers: ", size);
        scanf("%d", &target);

        for(x = 0; x < size; x++)
        {
             scanf("%d", &array1[x]);

        }

        prev = array1[0];

        for (i = 1; i < size; i++) 
        {
             if (array1[i] == prev) 
             {
                 count++;
             } 
             else 
             {
                 if (count < 2)
                     printf("%d=%d\n", prev, count);
                 prev = array1[i];
                 count = 1;
             }

        }

        if (count < 2)
        {
             printf("%d=%d\n", prev, count);
        }

        return 0;
   }

Answer 1

I’m confused by your code though, but the error is obvious. For example, if the input array is 9 8 7 9 8 7 9, the prev should be 9 at first iteration and when i == 1, prev == array1[i] is false. And we come to the else clause, of course the count is only 1 now. I suggest you rewrite the whole things… Either build a array to store the frequency of each entry, or sort the array.