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Home/ Questions/Q 8123049
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T06:02:29+00:00 2026-06-06T06:02:29+00:00

my code is <div id=fields> <form id=question-form> <input type=hidden name=question-main value=<?php echo mysql_prep($_GET[‘ques’]);?> /></form>

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my code is

<div id="fields">
<form id="question-form">  <input type="hidden" name="question-main" value="<?php echo mysql_prep($_GET['ques']);?>" /></form>

<a class="vote-up-off">up vote</a>

<span class="vote-count-post"><?php echo $row["upvotes"]+$row["downvotes"];?></span>

 <a class="vote-down-off" id="<?php echo mysql_prep($_GET['ques']);?>" >down vote</a>

 <a class="star-off" href="#">favorite</a>
</div>

and my jquery code is

$("document").ready(function(){
$(".vote-up-off").click(function(){
// here i want the id of form field and votecountpost field which is up and down to this field
})
})

the div field repeats again and again as the field present on database.So i want to get the particular field id using jquery and will perform some action using jquery.
How to find this?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T06:02:31+00:00Added an answer on June 6, 2026 at 6:02 am
            $("document").ready(function () {
                $('.vote-up-off').live('click', function () {
                    var formId = $(this).parents('form').attr('id');
                    var voteCountPost = $(this).next('.vote-count-post').attr('id');
                });
            });
    

    for form u can add class=”VoteForm”. so that it take that form attribute id in parents(”).

            $("document").ready(function () {
                $('.vote-up-off').live('click', function () {
                    var formId = $(this).parents('form.VoteForm').attr('id');
                    var voteCountPost = $(this).next('.vote-count-post').attr('id');
                });
            });
    
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