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Home/ Questions/Q 7894085
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T07:18:13+00:00 2026-06-03T07:18:13+00:00

my code is public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); try { Log.d(response, starting city

  • 0

my code is

public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);

        try {
            Log.d("response", "starting city connection");
            HttpPost httppost = new HttpPost(
                    "http://10.0.2.2/wic3/wic2/mobile/verifyUser");

            ResponseHandler<String> responseHandler = new BasicResponseHandler();
            sessionResponse = SignUpActivity.httpclient.execute(httppost,
                    responseHandler);
            Log.d("session response", "" + sessionResponse);

            if (sessionResponse.equals("true")) {
                Intent intent = new Intent(SignUpActivity.this,
                        FeedListViewActivity.class);
                startActivity(intent);
            }

        } catch (Exception e) {
            Log.e("error", "Error in http connection" + e.toString());
        }

………….

my question is can i skip the 1st activity(or screen) and directly load some other screen depending on any condition???my intention was to load the home page (skip the login page) if a session already exists….in my case the sessionResponse is true but i still get the login page

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  1. Editorial Team
    Editorial Team
    2026-06-03T07:18:14+00:00Added an answer on June 3, 2026 at 7:18 am

    Instead of the following code

    Intent intent = new Intent(SignUpActivity.this,FeedListViewActivity.class);  
    startActivity(intent);
    

    Simply put setContentView(). setContentView() is the method that displays the screen in android to the User Interface. If you dont call this method then nothing will be displayed. You will see only a blank screen. Modify your above code as follows

    if (sessionResponse.equals("true")) 
         setContentView(R.layout.screen1);
    else  
         setContentView(R.layout.screen2);
    
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