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Home/ Questions/Q 6236637
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T10:53:06+00:00 2026-05-24T10:53:06+00:00

My code is simply as follows: file = ‘C:\\Exe\\First Version\\filename.exe’ os.system(file) When I run

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My code is simply as follows:

file = 'C:\\Exe\\First Version\\filename.exe'
os.system(file)

When I run this program, a Windows error is raised: can't find the file specified.

I found out the problem has to with the whitespace in the middle of “First Version”. How could I find a way to circumvent the problem?

P.S.: what if the variable ‘file’ is being passed as an argument into another function?

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  1. Editorial Team
    Editorial Team
    2026-05-24T10:53:06+00:00Added an answer on May 24, 2026 at 10:53 am

    Putting quotes around the path will work:

    file = 'C:\\Exe\\First Version\\filename.exe'
    os.system('"' + file + '"')
    

    but a better solution is to use the subprocess module instead:

    import subprocess
    file = 'C:\\Exe\\First Version\\filename.exe'
    subprocess.call([file])
    
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