Home/ Questions/Q 8552459
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-06-11T14:25:42+00:00

My code is simply intending to populate two drop down lists with the names

  • 0

My code is simply intending to populate two drop down lists with the names of teams and use the users selections to manipulate the points value of those teams. As a trivial example, pick 2 teams and add both their corresponding scores together.

My main problem is trying to get both the users team selection and the corresponding points stored in variables so I can use them. I’m not very familiar with using arrays or how to retreive the value I want.
I can retrieve just the name easily but when I try to retrieve both points and names it populates the ddl incorrectly with “array” in every position. (It’s hosted online here:

My code is below, I’m not sure if the problem is with how I’m creating my drop down list or how I’m retrieving the data.

Thanks for your help

<?
require_once 'login.php';
 $db_server = mysql_connect($db_hostname, $db_user, $db_password);
 if (!$db_server) die("Unable to connect to MySQL: " . mysql_error());
 mysql_select_db($db_database)
 or die("Unable to select database: " . mysql_error());

 $sql="SELECT team, points FROM teams";
 $result=mysql_query($sql);

 $options="";

 while ($row=mysql_fetch_array($result)) {        
$team[$row["team"]]=$row["points"];  
$options.="<OPTION VALUE=\"$team\">".$team. '</OPTION>';        
 }


 if (isset($_POST['teamA'])) $teamA = $_POST['teamA'];
 else $teamA = "(Not entered)";
 if (isset($_POST['teamB'])) $teamB = $_POST['teamB'];
 else $teamB = "(Not entered)";

 $teamA = htmlspecialchars($teamA);
 $teamB = htmlspecialchars($teamB);

 ?>
 <body>
 You picked <?php echo $teamA; ?>(with <?php echo $team[$teamA]; ?> points) 
 and <?php echo $teamB; ?>(with <?php echo $team[$teamB]; ?>) 
 </br>

 <form method="post" action="ddl.php">

 Team A: 
 <SELECT NAME=teamA>
 <OPTION VALUE=0>Choose
 <?=$options?>
 </SELECT>

 Team B:
 <SELECT NAME=teamB>
  <OPTION VALUE=0>Choose
  <?=$options?>
  </SELECT>

  <input type="submit" />

  </form>
   </body>
Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. Editorial Team

    The problem is how you are building your SELECT list. The correct code would be something like this:

    while ($row=mysql_fetch_array($result)) {        
    $options.="<OPTION VALUE=\"{$row['team']}\">".htmlspecialchars($row['team']).'</OPTION>';        
}

    You don’t need to use $team variable.

    • 0