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Home/ Questions/Q 7892535
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Editorial Team
  • 0
Editorial Team
Asked: June 3, 20262026-06-03T06:53:43+00:00 2026-06-03T06:53:43+00:00

My code is $user_query = ‘ UPDATE users SET `password`=$password, `email`=$email, `position`=$position, WHERE `username`=.$uname.’;

  • 0

My code is

$user_query = '
     UPDATE  
          users  
     SET  
          `password`="$password",  
          `email`="$email", 
          `position`="$position", 
     WHERE  
          `username`=".$uname."';
$user_result = mysql_query($user_query, $connection);
confirm_query($user_result);

When I run this query it gives me an error:

Database query failed: You have an error in your SQL syntax;
check the manual that corresponds to your MySQL server version for the right syntax to use near ‘WHERE username=”.$uname.”‘ at line 7

Can any body help me resolve this error?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-03T06:53:44+00:00Added an answer on June 3, 2026 at 6:53 am

    Your query is in single quotes, so the variables aren’t parsed. As you can see in error, the string is literally

    `username`=".$uname."
    

    You need to either use double quotes around the enitre thing, to parse variables correctly.

    $user_query = "
     UPDATE  
          users  
     SET  
          `password`='$password',  
          `email`='$email', 
          `position`='$position'
     WHERE  
          `username`='$uname'";
    

    Or correctly use the string concatanation operator, ..

    $user_query = '
     UPDATE  
          users  
     SET  
          `password`="'.$password.'",  
          `email`="'.$email.'", 
          `position`="'.$position.'"
     WHERE  
          `username`="'.$uname.'"';
    

    As others have noted, there’s also an extra , after postion="$position".

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