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Home/ Questions/Q 9248203
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T09:53:56+00:00 2026-06-18T09:53:56+00:00

my code is yielding an unexpected result. It seems my for loop skips the

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my code is yielding an unexpected result. It seems my for loop skips the first iteration and I don’t understand why.

public static void main(String[] args) {

    Scanner get = new Scanner(System.in);
    int number;

    // Ex.1.

    String family_name;
    String[] family_array;

    System.out.println("Enter number of family members: ");
    number = get.nextInt();
    family_array = new String[number];

    for(int i = 0; i < number; i++){
        System.out.println("Enter family member name: ");
        family_name = get.nextLine();
        family_array[i] = family_name;
    }

    for(int i = 0; i < number; i++){
        System.out.println(family_array[i]);
    }

}

Returns… (pretend the number input are names)

Enter number of family members: 
5
Enter family member name: 
Enter family member name: 
1
Enter family member name: 
2
Enter family member name: 
3
Enter family member name: 
4

1
2
3
4

Why is the first get.nextLine() skipped?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-18T09:53:57+00:00Added an answer on June 18, 2026 at 9:53 am

    Currently your call to Scanner#nextInt is not consuming the newline character so it is being passed through to your first call of Scanner#nextLine, therefore it does not block.

    You will need to add

    get.nextLine();
    

    after calling nextInt so that your first call to nextLine will block for IO.

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