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Home/ Questions/Q 7025467
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T23:58:44+00:00 2026-05-27T23:58:44+00:00

My code looks like this #define tr(c,i) for(typeof((c).begin() i = (c).begin(); i != (c).end();

  • 0

My code looks like this

#define tr(c,i) for(typeof((c).begin() i = (c).begin(); i != (c).end(); i++)

...

typedef vector<long> vl;
vl numbers;

...

tr(numbers, j) { // this is line 95
    ...
}

The code looks okay to me, but not to my compiler! Mercilessly, I am given the following errors:

code.cpp: In function ‘int main()’:

code.cpp:95:9: error: specialization of ‘std::vector::iterator’ after instantiation

code.cpp:95:9: error: expected primary-expression before ‘typeof’

code.cpp:95:9: error: expected ‘;’ before ‘typeof’

code.cpp:95:9: error: name lookup of ‘j’ changed for ISO ‘for’ scoping

code.cpp:95:9: note: (if you use ‘-fpermissive’ G++ will accept your
code)

code.cpp:95:9: error: no match for ‘operator!=’ in ‘j !=
numbers.std::vector<_Tp, _Alloc>::end with _Tp = long int, _Alloc =
std::allocator, std::vector<_Tp, _Alloc>::iterator =
__gnu_cxx::__normal_iterator >, typename std::_Vector_base<_Tp, _Alloc>::_Tp_alloc_type::pointer =
long int*’

What am I missing here?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T23:58:44+00:00Added an answer on May 27, 2026 at 11:58 pm

    You have a missing parenthesis in the macro.

    #define tr(c,i) for(typeof((c).begin() i = (c).begin(); i != (c).end(); i++)
                                          ^
                                     Need ) here
    

    Try fixing that and see what errors you get.

    Minor note 1: When iterating, use ++i instead of i++ as the former can often faster for iterators.

    Minor note 2: typeof is a GCC specific extension. Your code will not compile on other compilers.

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