my code right now checks if they user types in “r” for customer type if not it throws an error message, I want it to also check if the user types in “c” because that’s also a valid customer type. I tried using in “else if” statement after the first “if” so i can check if its not r then is it c if not throw an error message but it wont work????
public static void main(String[] args)
{
Scanner sc = new Scanner(System.in);
String choice = "y";
while (!choice.equalsIgnoreCase("n"))
{
// get the input from the user
System.out.print("Enter customer type (r/c): ");
String customerType = sc.next();
if (!customerType.equalsIgnoreCase("R"))
{
sc.nextLine();
System.out.println("Error! Invalid Customer Type. Try Again ");
continue;
}
else
System.out.print("Enter subtotal: ");
double subtotal = sc.nextDouble();
// get the discount percent
double discountPercent = 0;
if (customerType.equalsIgnoreCase("R"))
{
if (subtotal < 100)
discountPercent = 0;
else if (subtotal >= 100 && subtotal < 250)
discountPercent = .1;
else if (subtotal >= 250)
discountPercent = .2;
}
else if (customerType.equalsIgnoreCase("C"))
{
if (subtotal < 250)
discountPercent = .2;
else
discountPercent = .3;
}
//else
//{sc.nextLine();
//System.out.println("Error! Invalid Customer Type. Try Again ");
//continue;
//}
//else}
// {
// discountPercent = .1;
// }
// calculate the discount amount and total
double discountAmount = subtotal * discountPercent;
double total = subtotal - discountAmount;
// format and display the results
NumberFormat currency = NumberFormat.getCurrencyInstance();
NumberFormat percent = NumberFormat.getPercentInstance();
System.out.println(
"Discount percent: " + percent.format(discountPercent) + "\n" +
"Discount amount: " + currency.format(discountAmount) + "\n" +
"Total: " + currency.format(total) + "\n");
// see if the user wants to continue
System.out.print("Continue? (y/n): ");
choice = sc.next();
System.out.println();
}
}
Well, If I don’t missunderstanding your questions, you want validate if the user only input r and c for customer type.
So, just add another condition in your if statement.
Try this :