Question

my code

<table id="mytable">
<tr>
    <td>Text 5</td>
    <td>Other text 5</td>
    <td><input name="name5" value=""></td>
    <td><input type="checkbox" value="5" name="records"></td>
</tr>
<tr>
    <td>Text 7</td>
    <td>Other text 7</td>
    <td><input name="name7" value=""></td>
    <td><input type="checkbox" value="7" name="records"></td>
</tr>
<tr>
    <td>Text 13</td>
    <td>Other text 13</td>
    <td><input name="name13" value=""></td>
    <td><input type="checkbox" value="13" name="records"></td>
</tr>
</table>

get the middle input checkbox with

$('#mytable input[type=checkbox][name=records][value=7]')

good 🙂

now, how can i get the prev input () and the next () input?

i try

$('#mytable input[type=checkbox][name=records][value=2]').prev('input[type=checkbox]')

for prev, but not works 🙁

thanks 🙂

Answer 1

Assuming you have a reference to that middle checkbox in checkbox, and also assuming that there is only going to be one checkbox descendant of each tr element:

//Previous checkbox:
checkbox.closest("tr").prev().find(":checkbox");

//Next checkbox:
checkbox.closest("tr").next().find(":checkbox");

This gets the ancestor tr element with .closest(), and then uses .prev() or .next() to select the previous or following tr, and then finds any checkbox descendants of that.

Also note the use of the :checkbox selector, which is basically a shortcut to the attribute selector you are currently using. You can use either, but the attribute selector is probably a bit faster since it’s a native CSS selector.