Question

My current host doesn’t allow remote mysql acces so I need to work around it by having script1 on server1 communicate with script2 on server2. I am trying to send post data to script2, which then takes that data and puts it into mysql. To keep my question simple I stripped the code down to this:

script1

for ( $counter = $counternumbernao; $counter <= $amountofcomments; $counter += 1) 
{
echo'
<form action="http://server2.x.com/form-receive.php" method="post">
<INPUT TYPE=HIDDEN NAME="comment_content" value=$comment_content>
<INPUT TYPE=HIDDEN NAME="comment_date" value=$comment_date">
<input type="submit" />
</form>
';
}

How can I alter this code, so that every time the loop occurs it automatically sends the $_POST data to script2, which then puts it into mysql? I didn’t think it was necessary to include script2 as it’s not important to this issue.

Answer 1

To have this automatically occur without the end user being aware of this behaviour, the best way would be to use CURL (http://php.net/manual/en/book.curl.php).

Here’s an example of how it would look:

$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, "http://server2.x.com/form-receive.php");
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_POST, true);

$data = array(
    'foo' => 'bar',
    // Put data from $_POST here
);

curl_setopt($ch, CURLOPT_POSTFIELDS, $data);
$output = curl_exec($ch);
$info = curl_getinfo($ch);
curl_close($ch);