Question

My current query (doesn’t work)

SELECT url
FROM table
WHERE
    'http://www.longurl.com/some/string' like '%' . url . '%'

table

url
longurl.com

I am trying to match the record in “table” for longurl.com to any compared URL that contains longurl.com.

Should match compared URLs such as:

http://www.longurl.com/some/string
http://longurl.com
http://longurl.com/some/string

In this PHP example, it is very easy to compare:

$url = "http://www.longurl.com/some/string";    
if(strstr($url, 'longurl.com')) {
    echo "success";
} else {
    echo "failure";
}

Answer 1

Okay, what about:

SELECT url 
  FROM table 
 WHERE INSTR('http://www.longurl.com/some/string', url) > 0

(Formatting didn’t work so well in the comments, so I added it again as an answer.)