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Home/ Questions/Q 6732527
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T10:39:42+00:00 2026-05-26T10:39:42+00:00

My current query looks like this: SELECT DISTINCT (member), count( UID ) AS numUID

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My current query looks like this:

SELECT DISTINCT (member), count( UID ) AS numUID
FROM memberdata
GROUP BY Member
ORDER BY count( UID ) DESC

What I get back, looks a lot like this:

A name 1    175
A name 2    38
A name 3    37
A name 4    36
A name 5    36

What I want to do now is get the count of numUID, in the above example I may get a result like:

**numUID**   **COUNT**
   175           1
   38            1
   37            1
   36            2

I’ve searched far and wide, but I can’t seem to get the information I need to put this query together properly. Any help would be appreciated.

Thanks,

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T10:39:43+00:00Added an answer on May 26, 2026 at 10:39 am

    Use a subselect and another GROUP BY:

    SELECT numUID, COUNT(*)
    FROM (
        SELECT member, count(UID) AS numUID
        FROM memberdata
        GROUP BY Member
    ) T1
    GROUP BY numUID
    

    I should also warn you that you are also misusing DISTINCT. When you use DISTINCT it always looks at the entire row. Writing DISTINCT(x) , y is exactly the same as DISTINCT x, y. When you use GROUP BY it is guaranteed that you will only get one row per group. There is no need to use DISTINCT here.

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