Question

My database table have 5 columns: ‘id’, ‘date_visited’, ‘page_title’, ‘ip’ and ‘total_views’.
I am not able to display ORDER BY ‘date_visited’.
My PHP Query is:

<?php
[...]
$query = "SELECT *,count(*) FROM table WHERE ip GROUP BY page_title";
$result = mysqli_query($link,$query) or die(mysqli_error($link). "Q=".$query);
if(!$result == 0) {
    while ($row = mysqli_fetch_array($result)) {
        $dataList_br .= '<tr>
                            <td>' .$row['date_visited']. '</td>
                            <td>' .$row['page_title']. '</td>
                            <td>' .$row['count(*)']. '</td>
                        </tr>';
    }
} else {
    $dataList_br .= '<p class="warning">No data found in database.</p>';
}
?>

When it outputs, it displays [date][page title] and [total views].
Please someone help me, how do I display last date from the query, instead now it displays the very first day the page was visited.

Thank you.

Answer 1

MySQL is lenient about the contents of the GROUP BY and will return a row for the group somewhat arbitrarily if columns aren’t in the GROUP BY but are SELECTed. In your case, it just gave you the first row (lowest date) for each group.

Get the page_name of the row with the MAX(date_visited) per group and join that against the main table to pull in the remaining columns from the main table.

SELECT
  table.id,
  table.ip,
  table.total_views,
  maxdates.date_visited,
  maxdates.page_name,
  maxdates.thecount
FROM
  table
  JOIN (
    /* Subquery returns the aggregates to join against 
       the main table so other columns can be pulled in */
    SELECT 
      page_title, 
      MAX(date_visited) AS maxdate, 
      COUNT(*) AS thecount 
    FROM table 
    GROUP BY page_title
  ) maxdates
    ON table.page_name = maxdates.page_name 
       AND table.date_visited = maxdates.maxdate