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Home/ Questions/Q 800085
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T23:14:11+00:00 2026-05-14T23:14:11+00:00

My example is as below. I found out the problem is with const in

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My example is as below. I found out the problem is with “const” in function void test’s parameter. I don’t know why the compiler does not allow. Could anybody tell me? Thanks.

vector<int> p;

void test(const vector<int> &blah)
{
   vector<int>::iterator it;
   for (it=blah.begin(); it!=blah.end(); it++)
   {
      cout<<*it<<" ";
   }
}

int main()
{
   p.push_back(1);
   p.push_back(2);
   p.push_back(3);
   test(p);

   return 0;
}
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  1. Editorial Team
    Editorial Team
    2026-05-14T23:14:11+00:00Added an answer on May 14, 2026 at 11:14 pm

    An iterator is defined as returning a reference to the contained object. This would break the const-ness of the vector if it was allowed. Use const_iterator instead.

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