Question

My file looks like:

L   0   256 *   *   *   *   *
H   0   307 100.0   +   0   0
S   30  351 *   *   *   *   *
D   8   27  *   *   *   *   99.3    
C   11  1   *   *   *   *   *   

for my script I would like to start by awk print $0 for certain lines using $1

Such as

awk '{if ($1!="C") {print $0}  else if ($1!="D") {print $0}}'

But, there has to be a way to combine "C" and "D" into one IF statement… right?

For example if I want to search for == L,H,S ie… NOT C or D how would I right this?

Answer 1

Your present condition is not correct as both $1!="C" and $1!="D" can’t be false at the same time. Hence, it will always print the whole file.

This will do as you described:

awk '{if ($1!="C" && $1!="D") {print $0}}'  file