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Home/ Questions/Q 9252283
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T10:54:23+00:00 2026-06-18T10:54:23+00:00

My first post, most questions already solved using this friendly provided knowldge here. But

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My first post, most questions already solved using this friendly provided knowldge here. But now I run out of ideas, again with a question about handling of poison characters in cmd.exe.

Let’s assume there is a given string variable enclosed in double quotes. Most poison characters has already been replaced by common chars before, the left ones disturbing the script are “&”, “(“, “)” and “%”. The string must be echoed to a file without quotes afterwards. So I had the idea to escape the poison characters tripled:

@echo off & setlocal ENABLEEXTENSIONS
SET AlbumArtist=%1
CALL :EscapePoisonChars %AlbumArtist% AlbumArtist_VDN

SET "FlacHyperLink==hyperlink^("file://%AlbumArtist_VDN%"^;"LossLess"^)")
echo %FlacHyperLink%
echo %AlbumArtist_VDN%

endlocal &GOTO:EOF

:EscapePoisonChars
@echo off & setlocal ENABLEEXTENSIONS
SET TmpString=%1
SET TmpString=%TmpString:&=^^^&%
SET TmpString=%TmpString:(=^^^(%
SET TmpString=%TmpString:)=^^^)%
endlocal&SET %2=%TmpString:~1,-1%&GOTO :EOF

When I call my script above I get the expected output – apart from the missing percent sign:

G:\YAET\20130204_Work>TryAmper.bat "100% Rock & Roll (7' UpMix)"
=hyperlink("file://100 Rock & Roll (7' UpMix)";"LossLess")
100 Rock & Roll (7' UpMix)

G:\YAET\20130204_Work>

I know that the percent can be escaped by itself. So “%%” will normally lead to a single literal “%”. But it was not possible for me to find a working replace procedure for percent signs because cmd always interprets it as a variable and tries to expand it. Is this the complete wrong direction to handle this issue or just misunderstanding of variable expansion? Any hints welcome! Thanks!

Cheers, Martin

Edit
Removed own code, see below Jeb’s answer for clean solution.

Thanks for help, Martin

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-18T10:54:24+00:00Added an answer on June 18, 2026 at 10:54 am

    Nice question!
    At first, yes you can replace even percent signs, but not within a percent expansion, you need a delayed expansion here.

    Setlocal EnableDelayedExpansion
    set tmpstr=!tmpstr:%=%%!
    

    But if you use the delayed expansion, you don’t need the escapes anymore, as the delayed expansion is the last phase of the batch parser and all characters lose any special meaning.
    You only need to echo with delayed expansion.

    Echo !tmpvar!
    

    EDIT: Clean solution

    @echo off
    setlocal DisableDelayedExpansion
    
    REM * More or less secure getting the parameter
    SET "AlbumArtist=%~1"
    
    setlocal EnableDelayedExpansion
    SET "FlacHyperLink==hyperlink("file://!AlbumArtist!";"LossLess")"
    
    echo !FlacHyperLink!
    echo !FlacHyperLink!> hugo.txt
    

    You need disableDelayedExpansion first, to get even exclamation marks from %1.
    After that, you should switch to delayed expansion and use it anywhere.

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