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Home/ Questions/Q 828257
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T03:41:53+00:00 2026-05-15T03:41:53+00:00

(my first post was not clear and confusing so I’ve edited the question) I

  • 0

(my first post was not clear and confusing so I’ve edited the question)

I was studying string manipulation.
You can use strlen() or substr() but cannot rely on other functions that are predefined in libraries.

Given string $string = "This is a pen", remove "is" so that
return value is "Th a pen" (including 3 whitespaces).

Remove ‘is’ means if a string is “Tsih”, we don’t remove it. Only “is” is removed.

I’ve tried (shown below) but returned value is not correct. I’ve run test test and
I’m still capturing the delimiter.

Thanks in advance!

function remove_delimiter_from_string(&$string, $del) {
    for($i=0; $i<strlen($string); $i++) {
        for($j=0; $j<strlen($del); $j++) {
            if($string[$i] == $del[$j]) {
                $string[$i] = $string[$i+$j]; //this grabs delimiter :(
            }
        }
    }
    echo $string . "\n";
}
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  1. Editorial Team
    Editorial Team
    2026-05-15T03:41:53+00:00Added an answer on May 15, 2026 at 3:41 am

    If you were allowed to use substr() it’d be so much easier. Then you could just loop it and check for the matched value, why can’t you use substr() but you can strlen() ?

    But without, this works at least:

    echo remove_delimiter_from_string("This is a pen","is");
    
    function remove_delimiter_from_string($input, $del) {
        $result = "";
        for($i=0; $i<strlen($input); $i++) {
            $temp = "";
            if($i < (strlen($input)-strlen($del))) {
                for($j=0; $j<strlen($del); $j++) {
                    $temp .= $input[$i+$j];
                }
            }
            if($temp == $del) {
                $i += strlen($del) - 1;
            } else {
                $result .= $input[$i];
            }
        }
        return $result;
    }
    
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