Question

My following SQL is not working but when I use same regular expression in Java, it’s work fine

SELECT * FROM tbl WHERE REGEXP_LIKE
(MESSAGE, '^(92|0)?(3[0-9]{9})\\*([0-9]{4})\\*(([0-9]{3})|1000)$')

Please help what I am doing wrong.

i am comparing following string

03211234090*0000*75 

Answer 1

There is a bug in your search pattern: \\*. This should be \*, as you only need one \ to escape the *.

SELECT *
FROM tbl
WHERE REGEXP_LIKE(MESSAGE, '^(92|0)?(3[0-9]{9})\*([0-9]{4})\*(([0-9]{3})|1000)$')

The other problem is in the \*(([0-9]{3})|1000)$ part – the last part of your string. The string you have provided 03211234090*0000*75 does not end with three digits between 0-9 or “1000”.

$ means the string must end with the expression immediately preceding it.

As a solution try putting \*(([0-9]{2, 3})|1000)$ if your business logic allows this. This will allow the either two or three digits or 1000 after the last asterisk to be accepted and the row will be retrieved.